Math, asked by vandana263, 1 year ago

on sides AB and DC of rectangle ABCD,points F and E are chosen such that AFCE is a rhombus as shown in a figure.If AB=16cm and BC=12cm,then find EF.explain with method plz.

Answers

Answered by Riyakushwaha12345

Take E and F are the mid point of DC and AB respectively
Construction : join FA ,EC ,FE
And BC= 12cm
Therefore EF= 12cm
See the diagram in picture down

Attachments:

zest: it is wrong

Riyakushwaha12345: But we have to find EF

zest: after we get af then by draeing the diagram correctly we get ef =15

zest: drawing*

zest: i couldnt send one more pic

zest: or i could have explained you

Riyakushwaha12345: But you think that if rectangle has 12cm length then how could EF will 15cm

zest: but length is always the greater one and ot is 16 cm and af 12.5 and then ef 15 cm

zest: ab 16 cm*

Answered by zest

applying condition for rhombus we get af =12.5
then apply Pythagoras theorem and u will get EF^2 =9^2+12^2 by drawing the diagram correctly

Attachments:

zest: af=11

zest: 12.5

zest: one more pic

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