Math, asked by Aditya9298, 7 months ago

on simplification -3a^2-[2a^2-(4a^2+b^2)] the value is​

Answers

Answered by ramadeva
2

Step-by-step explanation:

-3a^2-[2a^2-(4a^2+b^2)]

by distribution property

-3a^2 x -2a^2+-3a^2 x (4a^2+b^2)

6a^4+(-3a^2 x 4a^2+ -3a^2 x b^2)

6a^4+ -12a^4+ -3a^2b^2

-6a^4+-3a^2b^2

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