Question

on simplifying [(1/2)^-2]+[(2/3)^-2]-[(3/4)^-2]
a. 35/36
b. 161/36
c. -1/6
d. 23/36
please give answer with explanation
do not give unusual answer​

Answer 1

Answer:

b.161/36

Step-by-step explanation:

NOTE :

• a ^-1 = 1/a
• ( 1/a ) ^ -1 = (a/1)^1 = a

[(1/2)^-2]+[(2/3)^-2]-[(3/4)^-2]

=> [( 2 )^2 ] + [( 3/2 )^2] - [( 4/3 )^2 ]

=> [ 4 ] + [ 9/4 ] - [ 16/9 ]

=> 144+81-64 ( LCM )

36

=> 161

36

Answer 2

Answer:

4+9/4-16/9

144/36+81/36-64/36

161/36

1/a^-1=a

a^-1=1/a