Question

On simplifying (2x^3 – 4x^2 – 6x + 8) ÷ 2x, we get?

Answer 1

$\Rightarrow x^2-2x-3+\dfrac{4}{x}$

Step-by-step explanation:

$(2x^3-4x^2-6x+8)\div(2x)$

Divide the polynomial :-

distribute denominator with each numerator

$\Rightarrow \dfrac{2x^3}{2x}-\dfrac{4x^2}{2x}-\dfrac{6x}{2x}+\dfrac{8}{2x}$

$\Rightarrow x^2-2x-3+\dfrac{4}{x}$

#BAL

Answer 2

Answer:

right answer in the above answer