Question

On simplifying, x(y-z)+y(z-x) + z(x-y), we get​

Answer 1

Answer:

$\mathrm{x\left(y-z\right)+y\left(z-x\right)+z\left(x-y\right)=0}$

Step-by-step explanation:

$\mathrm{x\left(y-z\right)+y\left(z-x\right)+z\left(x-y\right)}$

$\mathrm{=xy-xz+y\left(z-x\right)+z\left(x-y\right)}$

$\mathrm{=xy-xz+yz-xy+z\left(x-y\right)}$

$\mathrm{=xy-xz+yz-xy+xz-yz}$

$=0$