Question

On solving sec square theta +tan square theta is equal to 5÷3 then what is the value of theta

Answer 1

Answer:

${ \sec( \alpha ) }^{2} + { \tan( \alpha ) }^{2} = \frac{5}{3} \\ 1 + { \tan( \alpha ) }^{2} + { \tan( \alpha ) }^{2} = \frac{5}{3} \\ 2 { \tan( \alpha ) }^{2} = \frac{5}{3} - 1 \\ \tan( \alpha ) = \frac{1}{ \sqrt{3} } \\ \alpha = 30$

PLS MARK AS BRAINLIEST