Question

On solving the pair of equations 2x-y=2;5x+2y=14 by substitution method, values of x and y :-
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Answer 1

2x-y=2

5x+2y=14

2x-y=2

2x=2+y

X=2+y/2

5x+2y=14

5(2+y/2)+2y=14

10+5y/2+2y=14

10+5y+4y/2=14

10+9y=14(2)

9y+10=28

9y=28-10

9y=18

y=18/9

y=2

2x-y=2

2x-2=2

2x=2+2

2x=4

X=4/2

X=2

:. X=2

y=2

Answer 2

Given:

Equations: 2x-y=2; 5x+2y=14

To find:

The values of x and y

Solution:

The required values of x and y are 2 and 2.

We can obtain the values required by calculating the value of y from an equation and substituting it in the other.

The given equations are-

2x-y=2; 5x+2y=14

On solving 2x-y=2, we get

2x-2=y

2(x-1)=y

Now, we will put this value of y in 5x+2y=14.

5x+2y=14

5x+2(2x-2)=14

On solving,

5x+4x-4=14

9x=14+4

9x=18

x=18/9

x=2

We will obtain y's value by using x=2.

y=2(x-1)

y=2(2-1)

y=2

Therefore, the required values of y and x are 2, 2.