Question

on square track of edge length 100m an athlete starts from one corner and reaches diagonally opposite corner. Find the distance and the magnitude of displacement of the athlete.
$(200m \sqr100 \sqrt{2m} }$
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Answer 1

Given :-

• AB = 100 m

• BC = 100 m

To find :-

• Distance = ?

• Magnitude of displacement (AC) = ?

Solution :-

$\rm\:Total\:Distance=AB+BC$

$\rm\:Total\:Distance=100m+100m$

$\rm\:Total\:Distance=200\:m$

Hence,the distance will be 200 m.

Now,

$\rm\:Displacement\:(AC)=\sqrt{{(AB)}^{2}+{(BC)}^{2}}$

$\rm\:Displacement\:(AC)=\sqrt{{(100)}^{2}+{(100)}^{2}}$

$\rm\:Displacement\:(AC)=\sqrt{10000+10000}\:m$

$\rm\:Displacement\:(AC)=\sqrt{20000}\:m$

$\rm\:Displacement\:(AC)=100\sqrt{2}\:m$

Hence,the magnitude of displacement will be 100√2 m.