Science, asked by lionrbl6, 8 months ago

On strong heating ______ compound,
decomposes to form ____and
steam. The residue is yellow when hot and white when cold.

ZnOH, Zno

Zn(OH)2, Zn20

Zn(OH)2, Zno

None​

Answers

Answered by aaravs618gmailcom
1

Answer:

Zinc carbonate (A) is the white amorphous solid which on heating gives colourless gas (B) which is carbon dioxide and the residue (C) which is zinc oxide.

ZnCO

3

Δ

B

CO

2

+

C

ZnO

Carbon dioxide gas turns lime water milky and zinc oxide is yellow when hot and white when cold.

Zinc oxide dissolves in dilute HCl to form zinc chloride which reacts with potassium ferrocyanide to form white ppt.

Zinc carbonate dissolves in dil HCl to liberate carbon dioxide gas (B).

ZnCO

3

+2HCl→ZnCl

2

+H

2

O+CO

2

Ammonium hydroxide neutralizes excess HCl.

Zn(II) ions react with hydrogen sulphide to give a white ppt D which is ZnS.

Zn

2+

+S

2−

→ZnS↑

Zn(II) ions react with NaOH to form white precipitate E which is zinc hydroxide.

Zn

2+

+2NaOH→

white ppt, E

Zn(OH)

2

This ppt dissolves in excess NaOH

white ppt, E

Zn(OH)

2

+2NaOH→

sodium zincate

Na

2

ZnO

2

+2H

2

O

Answered by sakshi0305
0

Answer:

This is what I feel

Explanation:

3) Zn(OH)2, ZnO

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