on suspending a body with a spring of force constant 100N/m its length increased by 2cm find the work done in this process
Answers
Answered by
0
Answer:
hope it will help you
Explanation:
Given,
Time period of SHM is one spring and mass is connected
Spring constant, k
Attached mass, m
So, frequency is, f=2π
m
k
As in the figure, if another spring is added in parallel.
Both spring identical, new spring constant for two parallel spring.
k
new
=k+k=2k
Time period of oscillation,
f
new
=2π
k
new
m
=2π
2k
m
f
new
=
2
1
2π
k
m
=
2
f
Hence, new frequency is
2
f
Similar questions