Question

on the annual day of school age wise participation of students in is in the given following distribution table ​

Answer 1

Median = 13.6

Step-by-step explanation:

To find Median class

= value of $(\frac{n}{2})^{th}$ observation

= value of $(\frac{76}{2} )^{th}$ observation

= 38th observation

From the column of cumulative frequency cf. We find that the 38th observation lies in the class 12 - 14.

∴ The median class is 12 - 14

Now,

∴ L = lower boundary point of median class = 12

∴ n = Total frequency = 76

∴ cf = Cumulative frequency of the class preceding the median class = 22

∴ f = Frequency of the median class = 20

∴ c = class length of median class = 2

Median $M=L+\frac{\frac{n}{2}-cf}{f}\times c$

$=12+\frac{38-22}{20}\times 2$

$=12+\frac{16}{20}\times 2$

= 12 + 1.6

= 13.6

Median = 13.6