Physics, asked by BrainyRukie, 9 months ago

on the basis of dimensions, decide which of the following relations for the displacement undergoing simple harmonic motion is not correct:
a. y= a sin 2 nt/T
b. y= a sin vt
c. y= a/T (sin (t/a)
d. y= a2^1/2 (sin nt/T-cos 2nt/T)​

Answers

Answered by shivanandaravikumar
2

Answer:

B.  y = a sin vt

Hope u like it :D

Answered by chrisjordan
1

Explanation:

Correct option is

B

y=asinvT

C

y=

T

a

sin(

a

t

)

b.,c.: In option (a) and (d) the dimensions of y and a in L.H.S. and R.H.S. are equal to L and while in option (b) angle is v.t (where v is velocity)

∴ dimension of v.t is [LT

−1

][T]=[L].

So sinvt is not dimensionless so option (b) is wrong. In option (c) in R.H.S. dimension of amplitude

T

a

=

[T]

[L]

=[LT

−1

] which not equal to the dimension of y i.e L and angle

a

t

=

[L]

[T]

=[LT

−1

] is not dimensionless.

Hence, verifies the option (b) and (c).

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