on the basis of electronic configuration which of the following iron has maximum number of unpaired electron Na+,Mg2+,Fe2+ ,Fe3+
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Hey there!
In order to find The maximum no. Of unpaired electrons ..we will first write their electronic configuration :
• Na+ ---> 1s2, 2s2, 2p6
• Mg+2 ----> 1s2 ,2s2, 2p6
• Fe+2 ----> 1s2, 2s2, 2p6, 3s2, 3p6,
4s2, 3p4
• Fe+3 ----> 1s2 , 2s2, 2p6, 3s2, 3p6,
4s2, 3p3
Now , unpaired electrons in
¤ Na+ = 0
¤ Mg+2 = 0
¤ Fe+2 = 2
¤ Fe+3 = 3
So as clear from above... The maximum unpaired electrons are present in Fe+3
# hope it helps!
In order to find The maximum no. Of unpaired electrons ..we will first write their electronic configuration :
• Na+ ---> 1s2, 2s2, 2p6
• Mg+2 ----> 1s2 ,2s2, 2p6
• Fe+2 ----> 1s2, 2s2, 2p6, 3s2, 3p6,
4s2, 3p4
• Fe+3 ----> 1s2 , 2s2, 2p6, 3s2, 3p6,
4s2, 3p3
Now , unpaired electrons in
¤ Na+ = 0
¤ Mg+2 = 0
¤ Fe+2 = 2
¤ Fe+3 = 3
So as clear from above... The maximum unpaired electrons are present in Fe+3
# hope it helps!
Anonymous:
Excellent answer!
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