On the basis of following thermochemical data, the value of enthalpy of formation of OH- ion at 25o C is ?
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well where is the thermochemical data??
but I can help if u are asking for this
ΔfGo H+(aq)=0H2O(l)→H+(aq)+OH−(aq) ΔH = 57.32 KJ H2 (g) + 12O2 (g)→H2O (l) ΔH = −286.20 KJTo find the enthalpy of formation of OH−, add these two equations:H2+12O2→H++ OH−ΔH = −286.20+57.32 = −228.88 KJΔfHo H+(aq)=0So, the ΔfHo OH− will be equal to − 228.88KJ
but I can help if u are asking for this
ΔfGo H+(aq)=0H2O(l)→H+(aq)+OH−(aq) ΔH = 57.32 KJ H2 (g) + 12O2 (g)→H2O (l) ΔH = −286.20 KJTo find the enthalpy of formation of OH−, add these two equations:H2+12O2→H++ OH−ΔH = −286.20+57.32 = −228.88 KJΔfHo H+(aq)=0So, the ΔfHo OH− will be equal to − 228.88KJ
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