Question

On the basis of the following E° values, the
strongest oxidizing agent is :
[Fe(CN)₆]⁴⁻ ⟶ [Fe(CN)₆]³⁻ + e⁻¹; E° = – 0.35 V
Fe²⁺ ⟶ Fe³⁺ + e⁻¹; E° = – 0.77 V
(a) [Fe(CN)₆]⁴⁻ (b) Fe²⁺
(c) Fe³⁺ (d) [Fe(CN)₆]³⁻

Answer 1

$\boxed{\huge{\red{\mathfrak{Answer}}}}$

_________________________

(C) Fe³+

_________________________

Answer 2

Answer:

Explanation:we have been given the reduction potentials so by changing their sign they become oxidation potential.now compare