On the basis of the information available from the reaction :
43Al+O2→23Al2O3,ΔG=−827KJmol−1 of O2, the minimum e.m.f required to carry out electrolysis of Al2O3 is (F=96500Cmol−1)
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- 43Al+O2→23Al2O3,ΔG=−827KJmol−1 of O2, the minimum e.m.f required to carry out electrolysis of Al2O3 is (F=96500Cmol−1).
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