Question

On the basis of VSEPR theory, draw the structure of XeF4 molecule.​

Answer 1

Explanation:

For drawing the structure we have to calculate its hybridization.

Calculation:

1/2×[V + M + A - C]

Here,

V = valence electron of central atom

M = no. of monovalent atom

A = charge of anion

C = charge of cation

In XeF4, central atom is Xe

So, Its V = 8

And M = 4 because 4 monovalent atom is present

Note:

• Atom which has its valency 1 is called monovalent atom.

There's no any charge. So, A and C = 0

Now,

1/2×[8+4+0-0]

1/2 × 12

6 (sp³d²)

So, Its hybridization is sp³d²

Shape: Square planar

structure: Refer to the attachment