Question

on the figure o is the centre of circle find the measurement of angle AOC in which Angle AOD=48°Angle AOD =31°​

Answer 1

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• AOD=48°Angle AOD =31°

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Join o & b

In ΔAOB

AO=BO

Angle AOB=OAB=30°

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In ΔBOC

OB= OC

Angle OBC= OCB= 40°

Angle ABO+ OBC= ABC

Angle ABC=30 +40

ANGLE ABC =70°

$angle \: abc \: \frac{1}{2} angle \: aoc$

$70° = \frac{1}{2} angle \: aoc \:$

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ANGLE AOC =140°

Answer 2

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