On the first of each month, Stacie runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:
Jan 41.55 July 36.38
Feb 42.51 Aug 38.48
Mar 43.01 Sept 41.87
Apr 39.76 Oct 51.32
May 37.32 Nov 42.59
June 35.28 Dec 43.71
Determine the difference between the mean of the data, including the outlier and excluding the outlier. Round to the hundredths place.
A. 1.21
B. 0.93
C. 40.98
D. 40.22
Answers
Answer:
Answer :) The difference between mean with outlier and mean without outlier is 0.93
Step-by-step explanation:
Total months are 12
So,
n=12
Sum of all values = 493.78
The mean is given by:
Mean = Sum of values/No. of values
= 493.78 / 12
= 41.148 minutes
The mean with outlier is: 41.148
Now to calculate the mean without outlier
We will subtract the outlier value from total sum
The outlier is 51.32 so the new sum will be: 493.78-51.32 =442.46
Total number of values = 12-1 = 11
The mean without outlier will be:
Mean without outlier = 442.46 / 11 = 40.233
Now the difference between both means is:
41.148 - 40.233 = 0.925 ⇒ 0.93
The difference between mean with outlier and mean without outlier is 0.93
Keywords: Mean, Average
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Answer:
0.93
Step-by-step explanation:
Got it right on my FLVS test.