on the horizontal surface of a truck a block of mass 1kg is placed 0.6 and truck is moving with acceleration 5m/sec2 then the frictional force on the block will be
Answers
Correct question :
On a horizontal surface in a truck , a block of mass 1 kg lies . The coefficient of a static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 m/s² , find the frictional force acting on the block .
Given :
Mass of the block ( m ) = 1 kg .
Coefficient of friction ( μ ) = 0.6 .
Acceleration of truck ( a ) = 5 m/s²
Force of friction = mass of the block × acceleration of the truck .
⇒ Force of friction = 1 kg × 5 m/s²
⇒ Force of friction = 5 kg m/s²
⇒ Force of friction = 5 N
The force of friction acting on the block will be 5 N .
Maximum value of friction = μ × mass × g
Take g = 9.8 m/s² and we will get :
Maximum value of friction = 0.6 × 1 kg × 9.8 m/s²
⇒ 5.88 kg m/s²
⇒ 5.88 N
The maximum value of friction will be 5.88 N .
EXPLANATION :
Friction acting will be 5 N but the maximum friction that will act on the block will be 5.88 N .
The friction will never exceed the value of 5.88 N which is the maximum value .