Math, asked by somokantasinghpel2pb, 10 months ago

On the Independence Day celebration in the school a number of stúdents participated in the celebration, School management has decided to distribute some sweets amongst the participants and the audience. If the total no. of sweets were represented by 8x4 + 14x3 - 2x2 + 7x - 8, each one received 2x² + 2x -1 sweets and 14x - 10 remained undistributed, find the no. of students to whom sweets were distributed.​

Answers

Answered by RvChaudharY50
4

Answer :-

Let number of students are y .

we know that,

Dividend = Quotient * Divisor + Remainder.

so,

→ 8x⁴ + 14x³ - 2x² + 7x - 8 = (2x² + 2x - 1) * y + (14x - 10)

→ 8x⁴ + 14x³ - 2x² + 7x - 14x - 8 + 10 = (2x² + 2x - 1) * y

→ 8x⁴ + 14x³ - 2x² - 7x + 2 = (2x² + 2x - 1) * y

→ y = 8x⁴ + 14x³ - 2x² - 7x + 2 / (2x² + 2x - 1)

dividing by long divison method ,

2x² + 2x - 1 ) 8x⁴ + 14x³ - 2x² - 7x + 2 (4x² + 3x - 2

8x⁴ + 8x³ - 4x²

6x³ + 2x² - 7x

6x³ + 6x² - 3x

-4x² - 4x + 2

-4x² - 4x + 2

0.

therefore,

→ Number of students are = (4x² + 3x - 2) (Ans.)

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

https://brainly.in/question/39026698

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