Question

On the level ground, the angle of elevations of a tower is 30° . On moving 20 m nearer, the angle of elevation is 60°. The height of the tower is​

Answer 1

Answer:

factorise the following the question x+2x²-2ab+-2

Answer 2

We have,

Angle of elvation¹=30°

Angle of elvation²=60°

Distance betweentwo elevation=20m

So total distance of ground=x+20

Tan30°=opp/adj

1/3 =opp/x+20