On the number line the solution set{-4 < x < 1, xe I}is represented as.
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Given: - 3 X 2 - 1 1 1 < 3 6 Taking L.C.M. of 3, 2 and 6 is 6.
X - 3×6 ≤X × 6-3×6 < 1 x < 2 x 6
-2x≤ 3x-8 < 1
⇒-2x≤ 3x - 8 and 3x - 8 < 1
⇒ 8 ≤ 3x + 2x
8 ≤ 5x
⇒ 3x < 1+8
⇒ 3x9
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5 <X ⇒x<3
... The solution set is {x: 1.6 ≤x≤
3, XER}
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