Question

on the same side of a tower, two objects are located .when observed from the top of the tower, their angles of depression are 45 degree and 60 degree. if the height of the tower is 150m, find the distance between the objects.

Answer 1

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Let AB be the tower of height 150m and Two objects are located when top of tower are observed, makes an angle of depression from the top and bottom of tower are 45degree and 60degree respectively.



Let CD = x, BD=y and angle(ADB)=60degree,  angle(ACB)=45degree

So we use trigonometric ratios.

In a triangle ABC,

tan45= 150/(x+y)
=> x+y = 150 ____eq(1)

Again in a triangle ABD,

tan60 = 150/y

=> root3 = 150/y

=> root3×y = 150_____eq(2)

So from (1) and (2) we get

X + 150/(root3) = 150

=> x(root3) = 150(root3-1)

=> X = 63.39 ______answer

Hence

the required distance is approximately "63.40m".

hope it will help you

Devil_king ▄︻̷̿┻̿═━一

Answer 2

Answer:

63.5

Step-by-step explanation:

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