Question

On the same side of a tower,two objects are locatedwhen observed from the top of the tower,their angle of depression are 45° and 60° if the height of the tower is 150m find the distance between the objects.​

Answer 1

Answer:

Find an answer to your question on the same side of a tower ... Let AB be the tower of height 150m and Two objects are Let An be the tower of height 150m and two objects are located when top of tower are observed, makes an angled of depression from the top and bottom of tower are 45 degree and 60 degree respectively .

Let CD =x , BD =y and

angled (ADB)= 60 degree

angle (ACB)= 45 degree

so we use trigonometry rations .

In a triangle ABC ,

tan 46 = 150/(x+y)

=x+y= 150 _eq(1)

again in a triangleABD,

tan60=150/y

=root3=150/y

= root3×y=150 _eq(2)

so from (1) and (2) we get

X+ 150 /(root 3)=150

=x(root3)= 150

=x(root3) = 150(root3-)

=X =63.39_ answer

Hence

The required distance is approximately "63.40m."

Step-by-step explanation:

Hope it Help You Please mark me Brainlist and follow me.

Answer 2

Answer:

HØla!MaTe

please refer to the given attachment