Question

On the smooth quarter circular surface of the
block, a particle is released from the state of
rest.
The coefficient of friction between the block and
the ground is u.
The block has mass M and
the particle has mass m.
Prove that the normal reaction acting on the particle after it has rotated by an
angle o measured with the horizontal, is equal to
N = 3mg sine
After that prove that the friction force needed from the ground to keep the block
in the state of rest is
Fr = 3mg sino cose
Thereafter, prove that the normal reaction acting on the block from the ground
is
Ny = Mg + 3mg (sine)?
Finally using trigonometry and the condition that requirement must be less than
or equal to the maximum available show that
- very difficult
>
, where K = M/3m
sum
(1+2K)2-1712
4K(1 +K)​

Answer 1

Answer:

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