Question

On the smooth table are placed two blocks in contact (I) A horizontal force of 5.0 N is applied on the 20 kg

Answer 1

Given the force and the mass, we can get the acceleration.

Force = mass × acceleration

The mass = 20kg

The force = 5 N

F = ma

5 = 2a

a = 5/2

a = 2.5 m/s²

The block accelerates from rest at an acceleration of 2.5 m/s²

Answer 2

Answer:

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Explanation:

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