Math, asked by Questioneriorr, 1 month ago

On the sum of money, the difference between the interest of the first year and interest of third year is rupees 210 rate than 10% per annum compounded annually find the sum invested.​

Answers

Answered by Ladylaurel
33

Answer :-

The sum of money invested is Rs. 10,000.

Step-by-step explanation

To Find :-

  • The sum of money invested.

Solution :-

Given that,

  • The difference between the interest of the first year and interest of third year is Rs. 210 rate being 10% per annum.

ㅤㅤㅤㅤㅤ Assumption

Let us assume the principal or the sum as Rs.100

Therefore,

Compound interest of 1st year =  \sf{\dfrac{100 \times 10 \times 1}{100}}

 \sf{\longrightarrow \: \dfrac{1 \cancel{00} \times 10 \times 1}{1 \cancel{00}}}

 \sf{\longrightarrow \: \dfrac{1 \times 10 \times 1}{1}}

 \sf{\longrightarrow \: Rs. 10}

∴ Amount is = Rs. 100 + Rs. 10 = Rs. 110

Compound interest of 2nd year =  \sf{\dfrac{110 \times 10 \times 1}{100}}

 \sf{\longrightarrow \: \dfrac{11\cancel{0} \times 1 \cancel{0} \times 1}{1 \cancel{0} \cancel{0}}}

 \sf{\longrightarrow \: \dfrac{11 \times 1 \times 1}{1}}

 \sf{\longrightarrow \: Rs. 11}

∴ Amount = Rs. 110 + Rs. 11 = Rs. 121

Compound interest of 3rd year =  \sf{\dfrac{121 \times 10 \times 1}{100}}

 \sf{\longrightarrow \dfrac{121 \times 1 \cancel{0} \times 1}{10 \cancel{0}}}

 \sf{\longrightarrow \dfrac{121 \times 1  \times 1}{10}}

 \sf{\longrightarrow \dfrac{121}{10}}

 \sf{\longrightarrow \cancel{\dfrac{121}{10}}}

 \sf{\longrightarrow Rs. 12.10}

Now, The difference between Compound Interest of 1st year and 3rd year is :-

 \sf{\longrightarrow Rs. 12.10 - Rs. 100}

 \sf{\longrightarrow Rs. 2.10}

According the question,

Let's find out, by applying Unitary method :-

We got,

The difference of interest in compound interest is Rs. 2.10, sum = Rs. 100

Therefore,

The difference of interest in compound interest is Rs. 210, The sum will be :-

 \sf{\longrightarrow \dfrac{100}{2.10} \times 210}

 \sf{\longrightarrow \dfrac{21000}{2.10}}

 \sf{\longrightarrow Rs. 10,000}

Hence, The sum invested is Rs. 10,000.

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