Question

on throwing a body to move upwards on maximum height at 40 its initial velocity will be? a.20√2m/s b.20m/s c.27.8m/s d.19m/s​

Answer 1

Explanation:

let initial velocity be u

final velocity will be zero at maximum height.

height covered =40

now apply ing v^2=u^2+2as

0 = u^2 +2(-10)40 g =10 is taken negative as body is going upward and upward direction is taken positive

u^2=2*10*40

=800

so u =√800= 20√2

option (A)