Question

on tossing a pair of dice the probability of getting an odd no. and a no. less than 4 is???????

Answer 1

P(odd number and number less than 4) = P(odd number in first die and number less than 4 in second die) + P(odd number in second die and number less than 4 in first die)

= 2 x 3/6 x 3/6

= 1/2.

Answer 2

Answer:

$\text{P( an odd number and number less than 4)}=\frac{1}{9}$

Explanation:

Let A be event of getting an odd number.

Let B be event of getting a number less than 4.

Formula:

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Sample space a pair of dice:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

$\text{P(A)}=\frac{27}{36}$

$\text{P(B)}=\frac{27}{36}$

$\text{P(A n B)}=\frac{4}{36}\Rightarrow \frac{1}{9}$