Question

on tossing two coins simultaneously, find the probability of getting no tail​

Answer 1

Answer:

Therefore, P(getting no tail) =P(E3)=n(S)n(E3)=41.

Answer 2

Answer:

Probability of getting no tail = 1/4.

Explanation:

The Sample space = { HH, HT, TH, TT}

Favourable Outcomes = { HH}