On treatment with H2O2 in an alkaline medium, K2Cr2O7 got converted into K3[Cr(O2)4] An anion of this compound consist of four peroxide bonds. During the reaction H2O2 got oxidised to O2(g) Moles of H2O2 required to completely reduce 1 mole of K2Cr2O7 in this reaction is _________
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Answer:
Step (i) K
2
Cr
2
O
7
+H
2
SO
4
→K
2
SO
4
+H
2
Cr
2
O
7
Step (ii ) [H
2
O
2
→H
2
O+(O)]4
Step (iii) H
2
Cr
2
O
7
+4(O)→2CrO
5
+H
2
O
Hence, K
2
Cr
2
O
7
+H
2
SO
4
+4H
2
O
2
→2CrO
5
+K
2
SO
4
+5H
2
O
The formation of Chromium Pentaoxide leads to the formation of blue colour from orange (as potassium dichromate is orange in colour). Chromium Pentaoxide is blue, so we get a blue colour after the reaction.
In the reaction, Hydrogen peroxide acts as an oxidizing agent, because it gets reduced, and its oxidation number changes to -2 from -1
Hence, the correct option is C
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