Physics, asked by sric, 1 year ago

on tripling the absolute temparture of the source ,the efficiency of carnot's heat engine becomes double that of the initial efficiency.Then the initial eficiency of the engine is

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Answered by saisrinivaschiru
0

Answer:

initial efficiency is 4/7

Explanation:

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Answered by Anonymous
0

Given - T1 new = 3T1

N new = 2N original

Find - N original

Solution - Efficiency and Temperature are related by the following formula-

N = 1-(T2/T1)

In the formula, n refers to efficiency, T2 is sink temperature and T1 is source temperature.

With respect to given values, keeping them in equation-

2Nnew = 1-(T2/3T1)

Replacing N with formula

2[1-(T2/T1)] = 1-(T2/3T1)

2T1-2T2/T1 = 3T1-T2/3T1

T2/T1 = 3/7

Keeping T2/T1 in original equation

N = 1-(3/7)

N = 4/7

Hence, Initial efficiency of engine is - 4/7

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