On turning a corner a car driver driving at 36km/h,finds a child on the road 55m ahead.
He immediately applies brakes,so as to stop within 5m of the child . Calculate the retardation produced and the time taken by the car to stop.
Answers
Answered by
1
Answer: acceleration=-12.96m/s
retardation = 12.96m/s
time=2.78s
Explanation:
Answered by
9
Answer: u=10 v=0 s=55-5=50
V2-u2=2as
10*2=2×50=1ms*
T=v-u/a. =0-10/1= 10sec.
Explanation:
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