Question

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$\mathfrak{Question}$$\green\implies$
The mass of a hydrogen molecule is$3.32 ×10^{-27}$kg.
If $10^{23}$ hydrogen molecules strike, per second, a fixed
wall of area 2 cm^2
at an angle of 45° to the normal, and rebound elastically with a speed of [tex]10^3
[/tex]m/s, then
what will be the pressure on wall approximately?

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Answer 1

$p = \frac{f}{a} = \frac{2.nmv \cos(θ) }{a} \: \\ = \: \: \frac{{2 \times {10}^{23} \times 3.32 \times {10}^{ - 27} \times {10}^{3} \: } \: } { \sqrt{2} \times 2 \times {10}^{ - 2} } \\ \:$

$= 2.35 \times {10}^{3} \: n/ \: {m}^{2}$

Answer 2

Answer:

bhai kya bakchodi wale swag mein @thequiet ko answer kiya hai. carryminati aaj kal kuch jada nahi bolta hai

hi mujhe bhai mat bolna behen bolo hehehehehehehehehhe