on
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EXER
. Find the sum of the following APs:
(i) 2,7,12,..., to 10 terms.
(iii) 0.6, 1.7, 2.8,..., to 100 terms
Answers
Answered by
2
Answer:
please explain your question clearly ☺️
Answered by
2
Answer:
(i) 2,7,12...... to 10
th
term
Here a=2,n=10
And d=7−2=5
S
n
=
2
n
[2a+(n−1)d]
S
10
=
2
10
[2(2)+(10−1)5]=5(4+9×5)=245
(iii) 0.6,1.7,2.8............ to 100 term
Here a=0.6,n=100
And d=1.7−0.6=1.1
S
n
=
2
n
[2a+(n−1)d]
S
100
=
2
100
[2(0.6)+(100−1)(1.1)]=50(1.2−99×1.1)=5505
this is the your answer
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