On Wednesday, a local hamburger shop sold a combined total of 261 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold. How many hamburgers were sold on Wednesday?
Answers
Step-by-step explanation:
Let x be the no. of hamburgers and y be the no. of cheeseburgers.
According to the question,
x+y=261...............(1)
2x=y.............(2)
put (2) in (1)
x+2x=261
3x=261
x=87
Therefore, the no. of hamburgers sold on wednesday were 87
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Let us assume that on Wednesday, a local hamburger shop sold 'M' hamburgers and 'N' cheeseburgers.
Given that, he sold a total of 261 hamburgers and cheeseburgers.
Hamburgers + Cheeseburgers = 261
Also given that, the number of cheeseburgers sold was two times the number of hamburgers sold.
Cheeseburgers = 2 × Hamburgers
Substitute value of N in M
Substitute value of M in N
Therefore,
The number of Hamburgers that were sold on Wednesday = 87 and Cheeseburgers = 174.
Verification
From the above calculations, we have a number of Hamburgers = M = 87 and Cheeseburgers = N = 174
Case 1.
“He sold a total of 261 hamburgers and cheeseburgers.”
⇒ M + N = 261
⇒ 87 + 174 = 261
Case 2.
“The number of cheeseburgers sold was two times the number of hamburgers sold.”
⇒ N = 2M
⇒ 174 = 2(87)
⇒ 174 = 174