Math, asked by shaletchacko28, 6 months ago

On weekend, all the tickets were sold and tickets in the last two rows only 15 seats are there and 70 seats are in the remaining part. Money collected at the counter was Rs. 21000. Write the linear equation in two variables for the given situation. ​

Answers

Answered by bhagyashreechowdhury
0

Given:

On weekend, all the tickets were sold and tickets in the last two rows only 15 seats are there and 70 seats are in the remaining part

Money collected at the counter was Rs. 21000

To find:

Write the linear equation in two variables for the given situation. ​

Solution:

Let's assume,

"x" → represents the price of the tickets of 15 seats on the last two rows

"y" → represents the price of the tickets of 70 seats in the remaining part

So,

The cost of the 15 seats on the last two rows = Rs. 15x

and

The cost of the 70 seats in the remaining part = Rs. 70y

Since all the tickets were sold and the money collected at the counter was Rs. 21000, therefore we can form the linear equation in two variables representing the given situation as:

→ 15x + 70y = 21000 ←

Thus, the linear equation ⇒ \boxed{\bold{\underline{15x\:+\:70y\:=21000}}}.

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Also View:

in a cinema hall 300 tickets were sold the total sale of ticket was rs 1250 if tickets were of two dinomenation of rs 2.5 and 5.00 how many of each Dinomenation were sold?

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In an Auditorium, seats were arranged in rows and columns. The number of rows was equal to the number of seats in each row. When the number of row was doubled and the number of seat in each row was reduced by 10, total number of seats increased by 300. Find :

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