On what factor does the petential gradient depend?
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Answered by
1
Solution :
The fall of potential across a potentiometer wire of length l is given by
$V=IR$
$\quad= \large\frac{I \rho l}{A}$
Potential gradient $k= \large\frac{v}{l} =\frac{I \rho}{A}$
$\qquad= k \infty I=>$ current passing through the potentio meter wire.
(ii) $k \infty \rho$ (ie) specific resistance of the material of the potentiometer wire.
(iii) $k \infty \large\frac{1}{A}$
(ie) area of cross section of the wire
The fall of potential across a potentiometer wire of length l is given by
$V=IR$
$\quad= \large\frac{I \rho l}{A}$
Potential gradient $k= \large\frac{v}{l} =\frac{I \rho}{A}$
$\qquad= k \infty I=>$ current passing through the potentio meter wire.
(ii) $k \infty \rho$ (ie) specific resistance of the material of the potentiometer wire.
(iii) $k \infty \large\frac{1}{A}$
(ie) area of cross section of the wire
twinkle1125:
thnx dear
Answered by
1
Solution :
The fall of potential across a potentiometer wire of length l is given by
$V=IR$
$\quad= \large\frac{I \rho l}{A}$
Potential gradient $k= \large\frac{v}{l} =\frac{I \rho}{A}$
$\qquad= k \infty I=>$ current passing through the potentio meter wire.
(ii) $k \infty \rho$ (ie) specific resistance of the material of the potentiometer wire.
(iii) $k \infty \large\frac{1}{A}$
(ie) area of cross section of the wire
The fall of potential across a potentiometer wire of length l is given by
$V=IR$
$\quad= \large\frac{I \rho l}{A}$
Potential gradient $k= \large\frac{v}{l} =\frac{I \rho}{A}$
$\qquad= k \infty I=>$ current passing through the potentio meter wire.
(ii) $k \infty \rho$ (ie) specific resistance of the material of the potentiometer wire.
(iii) $k \infty \large\frac{1}{A}$
(ie) area of cross section of the wire
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