Question

on what principal the amount will become ₹676 in 2 years at rate of 4% p.a intrest compounded annualy​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Principal=625\:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Amount(A) = 676 \: rupees \\ \\ \implies Time (t)= 2 \: years \\ \\ \implies Rate(r) = 4 \\ \\ \underline \bold{To \: Find : } \\ \implies Principal = ?$

• According to given question :

$\bold{Using \: formula \: of \: Compound \: Interest : } \\ \implies A = p(1 + \frac{r}{100} ) ^{t} \\\\\bold{Putting\:given\:values} \\ \implies 676 = p \times (1 + \frac{4}{100} ) ^{2} \\ \\ \implies 676 = p \times (1 + 0.04)^{2} \\ \\ \implies 676 = p \times {(1.04)}^{2} \\ \\ \implies 676 = p \times 1.0816 \\ \\ \implies p = \frac{676 }{1.0816} \\ \\\implies p=\frac{\cancel{676}\times10000}{\cancel{10816}}\\\\\implies p=0.0625\times 1000\\ \\ \bold{\implies p = 625 \: rupees}$

Answer 2

Answer____

• Principal = 625 rupees

Step-by-step explanation :

$\bold{using \: formula \: of \: compound \: interest : } \\ \implies a = p(1 + \frac{r}{100} ) ^{t} \\ \\ \implies 676 = p \times (1 + \frac{4}{100} ) ^{2} \\ \\ \implies 676 = p \times (1 + 0.04)^{2} \\ \\ \implies 676 = p \times {(1.04)}^{2} \\ \\ \implies 676 = p \times 1.0816 \\ \\ \implies p = \frac{676 }{1.0816} \\ \\ \bold{\implies p = 625 \: rupees}$