on what sum of money does the si for 5 years at 10 percent become 1200
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Answered by
2
Answer:
It is given that
S.I=Rs.1,600
R=5% p.a.
T=10 years
We know that P= (S.I×100) / (R×T)
Substituting the values =(1600×100)/(5×10)
=3200
So we get P=Rs.3,200
Answered by
2
S.I =1200
Time =5 years
Rate =10 percent
P =?
S.I.= P×R×T/100
1200=P ×10×5/100
1200×100/10×5 = P
1200×10/5=P
1200×2=60,000
P =60,000
I hope it helps
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