on what sum the compound interest for 3 years at 10% per annum will be rupees 1655
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A=P(1+R upon 100)3
A=p(11upon10)3
a=1655×11upon10×11upon10×11upon10
=a=23.485
ci=p_a
ci=1655-23.485
=1631.515
A=p(11upon10)3
a=1655×11upon10×11upon10×11upon10
=a=23.485
ci=p_a
ci=1655-23.485
=1631.515
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