Question

on what sum will be the compound interest for 2 years at 4% per annum Be rupees 5712

Answer 1

GIVEN :
Compound Interest (CI) = ₹5712
Time (n) = 2 years
Rate (R) = 4%

Let the principal (sum ) = P

Compound Interest (CI) = Amount - Principal

CI = A - P
5712 = A - P
A = 5712 + P

A=P(1+R/100)ⁿ
5712 + P = P(1+4/100)²
5712 + P =P (1 + 1/25)²
5712 + P = P(26/25)²
5712 + P = P(676/625)
5712 + P = 676 P /625
625P + 5712 × 625 = 676P
5712 × 625 = 676P - 625P
5712 × 625 = 51P
P = (5712 × 625)/51
P = 112 × 625
P = ₹ 70,000

Hence, the sum will be ₹ 70,000.

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

Step-by-step explanation:

Compound Interest (CI) = ₹5712

Time (n) = 2 years

Rate (R) = 4%

Let the principal (sum ) = P

Compound Interest (CI) = Amount - Principal

CI = A - P

5712 = A - P

A = 5712 + P

A=P(1+R/100)ⁿ

5712 + P = P(1+4/100)²

5712 + P =P (1 + 1/25)²

5712 + P = P(26/25)²

5712 + P = P(676/625)

5712 + P = 676 P /625

625P + 5712 × 625 = 676P

5712 × 625 = 676P - 625P

5712 × 625 = 51P

P = (5712 × 625)/51

P = 112 × 625

P = ₹ 70,000

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