on what sum will the compound interest at 15/2 pa for 3 years be 3101.40 annually
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amount = P (1+R/100)^N
CI= A-P=P (1+R/100)^N-P
OR,
3101.40=P( (1+15/200)^3-1)
=P (1.075^3-1)
=P*0.242296875
hence P=12800
CI= A-P=P (1+R/100)^N-P
OR,
3101.40=P( (1+15/200)^3-1)
=P (1.075^3-1)
=P*0.242296875
hence P=12800
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