Question

on what sum will the compound interest at 15/2% per annum for three years compounded annually be rupees 3101.40​

Answer 1

Answer:

talk Jack do

Step-by-step explanation:

may done is Jack had an idea so Jack do

Answer 2

Answer:

$p((1 + \frac{r}{100} ) ^{n} - 1) = 3101.40 \\ = p( \frac{43}{40} ) ^{3} - p = 3101.40 \\ = \frac{79507p}{64000} - \frac{64000p}{64000} = 3101.40 \\ = \frac{15507p}{64000} = 3101.40 \\ = p = \frac{3101.4 \times 64000}{15507} \\ = p = \frac{64000}{5} \\ = p = 12800$

the sum of money is 12800rs