On which day a hot day or a cold day an echo is heard sooner. Why?
Answers
Answered by
39
Speed of sound (c) is determined based on
C= square root of (YRT/m)
where,
Y=ratio of specific heat of air
R=Universal gas constant
m=molar mass of air
T=temperature of air
Y,R, and m are constant and only the variable is Temperature.
Thus speed of sound really depends on temperature.
So Echo will travel faster in warm/hot air compare to the cold air.
But strangly, in cold weather, you can hear things clearly for unknown reason.
If this helps, please mark as Brainliest.
C= square root of (YRT/m)
where,
Y=ratio of specific heat of air
R=Universal gas constant
m=molar mass of air
T=temperature of air
Y,R, and m are constant and only the variable is Temperature.
Thus speed of sound really depends on temperature.
So Echo will travel faster in warm/hot air compare to the cold air.
But strangly, in cold weather, you can hear things clearly for unknown reason.
If this helps, please mark as Brainliest.
Answered by
37
In depends upon the speed of sound that echo will be heard sooner or later and speed of sound in a gas depends on its composition and temperature. Temperature is directly proportional to speed of sound which means as temperature increases speed of sound increases and as it decreases so the speed decreases.
By Newton laplace equation speed of sound c is
c=square root (Ks/p)
Ks=stiffness coefficient
p=density
Speed of sound is inversely proportional to density p and density p is inversely proportional to temperature so by increasing temperature speed of sound will increase.
So we will hear echo sooner on a hot day.
By Newton laplace equation speed of sound c is
c=square root (Ks/p)
Ks=stiffness coefficient
p=density
Speed of sound is inversely proportional to density p and density p is inversely proportional to temperature so by increasing temperature speed of sound will increase.
So we will hear echo sooner on a hot day.
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