Once the Maths teacher of class IX told students that today we will prove that
the sum of all three angles is 180°. As shown in the figure. He told to draw any triangle ABC in the notebook Further side BC was extended to D.Now the teacher said to draw CE ll BA. Further angles were named 1 to 5 as shown in the figure. Now answer the following questions.
Q.(i).CE ll BA and AC is a transverse line.So ∠1 is equal to
a) ∠2
b) ∠3
c) ∠4
d) ∠5
Q.(ii). ∠2 is equal to Which equal ?
a) ∠2
b) ∠3
c) ∠4
d) ∠5
Q.(iii). What is the value of ∠3+∠4+∠5 ?
a) 180°
b) 120°
c) 200°
d)360°
Q.(iv). What is the value of ∠ACD=∠4+∠5 ?
a) ∠3+∠5
b) ∠1+∠2
c) ∠2+∠3
d) ∠3+∠4
Q.(v). What is the value of ∠1+∠2+∠3 ?
a) ∠3+∠4+∠5=180°
b) 360°
c) ∠3+∠4=180°
d) ∠3+∠5=200°
Q.(vi).What will be angle ∠ACD ?
a) ∠3+∠5
b) ∠3+∠2
c) ∠1+∠3
d) ∠1+∠2
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Answer:
(i)ans.(c)
(ii)ans(d)
(iii)ans(a)
(iv)ans(b)
(v)ans(c)
(vi)ans(d)
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pl sfree pooint
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