Once upon a time a Brahimin went to an Arrogant King and asked him to give him some money to survive but he made joke of him, And this made him embarrassed. That's why Brahmin decided to take revenge.
He asked The King to fulfill his wish and king agreed, but the brahmin demanded to take pledge that the king will satisfy his needs. King agreed, he thought that what a brahmin can take from him, just some money that's it.
Brahmin Demanded money equivalent to the total number of boxes in a chess board. He asked them to give him money in multiple of two.
for e.g. He will start from ₹ 1 from first box of chess in multiple of 2 in each successive box of chess.
₹1 in first box, 2×1 = ₹2 from second box and 2 × 2 = ₹4 from third box and goes on to 64 boxes.
Now, tell me, How much money that Brahmin will get, in Total ?
Attachments:
AkshithaZayn:
an answer slot is empty ;p
WHERE?
You are answering it
only one person answered. one is empty
You are answering it right now
as is showing in my pc
oh..I left. thats why I am commenting now ;p
who else reserved the ticket kindly dlt the answer
wait for 15 min it may be alright
okokokokokok
Answers
Answered by
1
It would be umm...
₹ 18,446,744,073,709,551,615
That means He is an owner of about 19 quantillion with no investment, Isn't it wicked?
₹ 18,446,744,073,709,551,615
That means He is an owner of about 19 quantillion with no investment, Isn't it wicked?
Attachments:
you didnt show the method of calculation
kindly correct it
there needs to be a method bt which you calculated this amount
you should have wrote this as answer
oooh ... but anyother mod reserved the ticket ... i cant give you edit option
Answered by
0
HELLO THERE!!
Same here: https://brainly.in/question/2814759
The above question is indeed an interesting one!!
According to my knowledge,The money that is to be given to the Brahmin will be calculated in GP series (Geometric Progression).
Why?
Note:For 1st box, he will get Rs.1For 2nd box, he will get Rs. 2 x 1 = Rs.2For 3rd box, he will get Rs. 2 x 2 = Rs.4
The common ratio of the money that he gets after each step is the same.Let the common ratio be r.
Common ratio of a GP series is calculated by dividing the second term by the first.
Hence, in this case,
So, r = 2.
Let the first term be a.Since, for the first box, he gets Rs. 1,a = 1.
Now we have to calculate the sum of this GP series. The resultant sum will denote the amount which he will receive.
Since the value of r is 2,it means that r > 1.n = 64.
So,refer to the picture to get the formula of the Sum of 64 terms (since there are 64 boxes in total) and the calculation....
So, the Brahmin shall get Rs. 18446744073709551615
Same here: https://brainly.in/question/2814759
The above question is indeed an interesting one!!
According to my knowledge,The money that is to be given to the Brahmin will be calculated in GP series (Geometric Progression).
Why?
Note:For 1st box, he will get Rs.1For 2nd box, he will get Rs. 2 x 1 = Rs.2For 3rd box, he will get Rs. 2 x 2 = Rs.4
The common ratio of the money that he gets after each step is the same.Let the common ratio be r.
Common ratio of a GP series is calculated by dividing the second term by the first.
Hence, in this case,
So, r = 2.
Let the first term be a.Since, for the first box, he gets Rs. 1,a = 1.
Now we have to calculate the sum of this GP series. The resultant sum will denote the amount which he will receive.
Since the value of r is 2,it means that r > 1.n = 64.
So,refer to the picture to get the formula of the Sum of 64 terms (since there are 64 boxes in total) and the calculation....
So, the Brahmin shall get Rs. 18446744073709551615
Attachments:
Similar questions