Question

one
16. Find k, if
of the lines given by
kar? + 10xy + 8y2 = 0 is perpendicular to the line
2x - y=5.
(2 marks)​

Answer 1

Answer:

plmnvcxzaqryoplkhfsazxvb

Step-by-step explanation:

ndkzlzlslzljdbdfvvfnskaksisudyedbbdns

Answer 2

Step-by-step explanation:

slope of 2x−y=5 is 2.

So the slope of a perpendicular line is

2

−1

kx

2

+10xy+8y

2

=0 is supposed to be the intersection of 2 straight lines so, lets solve it for y.

⇒ y=

16

−10x±

100x

2

−32kx

2

=

16

−10x±x

100−68k

=

16

x(−10±

100−32k

)

So the slope of the two lines is

16

(−10±

100−32k

)

∴

16

(−10±

100−32k

)

=

2

−1

⇒ −20±2

100−32k

=−16

⇒ ±2

100−32k

=4

⇒ ±

100−32k

=2

⇒ 100−32k=4 [ Squaring both sides ]

⇒ 32k=96

∴ k=3