Question

one airplane can accommodate 330 passengers. how many airplanes are required to accommadate seats for 990 passengers! ​

Answer 1

Explanation:

330 per plane

990 /330=3planes

Answer 2

$here \: is \: ur \: answer \: buddy \: \\ \\ mark \: as \: brainliest \: answer \: \: please \: my \: friend \: \: solution \: \: \\ \\ \: given \: \: \\ \\ 330 \: passengers \: per \: plane \: \\ then \: \\ \\ no.of.planes \: \: = \: \: \frac{990}{330} \\ \\ hence \: 3 \: planes \: are \: required \: to \: accomadate \: 990 \: passengers \: \: \\ \\ hope \: this \: will \: help \: u \: \\ \\ mark \: as \: brainliest \: \: answer \: \: please \: my \: friend \: \: \:$